How many planks each of which is $3 m$ long, $15 c m$ broad and $5 c m$ thick can be prepared from a wooden block $6 m$ long, $75 c m$ broad and $45 c m$ thick.

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Solution

The correct option is A 90
Length of the wooden block $= 6 m = 6 \times 100 c m (∵ 1 m = 100 m)$ = 600cm
Breadth of the block = 75cm
Height of the block = 45cm
Volume of the wooden block $= 600 \times 75 \times 45 = 20, 25, 000$ $c m^{3}$
Again it is that the length of a plank = 3 m
= 3 \times 100 cm = 300 cm $(∵ 1 m = 100 c m)$
Breadth = 15 cm, height = 5 cm
volume of the plane = lbh = $300 \times 15 \times 15 = 22, 500 c m^{3}$
$∴$ No. of such planks $= \frac{V o l u m e o f t h e w o o d e n b l o c k}{v o l u m e o f a p l a n k}$
$= \frac{2025000}{22500} = 90$

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How many planks each of which is 3 m long, 15cm broad and 5 cm thick can be prepared from a wooden block 6 m long, 75 cm broad and 45 cm thick.

How many planks each of which is $3 m$ long, $15 c m$ broad and $5 c m$ thick can be prepared from a wooden block $6 m$ long, $75 c m$ broad and $45 c m$ thick.