Question

How many points need to be selected so that there is a probability of at least $0.85$ that at least one point is closer to the centre than to the circumference?

• A. $5$
• B. $6$
• C. $7$
• D. $8$

Answer 1

The correct option is C $7$

To occur at least a probability of $0.85$

$P(X\le 1),$ i.e, atleast one point is closer to the center than the circumference.

$=\frac{37-\frac{30}{64}}{\frac{1}{64}}$

$=7$ Points.

Hence, the answer is $7.$