How many positive numbers from 1 to 200 both inclusive are equal to the cube of an integer?

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B 5
Here, $n^{3}$ varies from 1 to 200 (both 1 & 200 included)
$= 1 \leq n^{3} 200 = \sqrt[3]{1} \leq n \leq \sqrt[3]{200} = 1 \leq n \leq 5.848$
So, no. of positive integers equal to cube of an integer = 5 (1, 2, 3, 4, 5)

Suggest Corrections

Similar questions

- 18

33

200

400

50

100

29. How many integers from 0 to 50, inclusive, have a remainder of 1 when divided by 3?

1000

5

3

n

1

8

1

n

Join BYJU'S Learning Program