Question

How many possible solutions does 7x + y = 8 have, if x and y are natural numbers.

Answer 1

Given equation: $7x+y=8$
Also, $x$ and $y$ are natural numbers.
So, value of $x$, $y$ starts from $1,2,\mathrm{3.....}n$.
Now,
$7x+y=8$
check $(x,y)$ = $(1,1)$
Putting $x$ equal to $1$ and $y$ equal to $1$ we get,
$7+1=8$
$8=8$
True statement
So, the possible values are (1, 1).
Therefore, there is only 1 possible solution of equation $7x+y=8$.