How many primary volts must be applied to a transformer with a secondary to primary turns ratio of $0.1$ to obtain a secondary voltage of $9 V$ ?

9 V

No worries! We‘ve got your back. Try BYJU‘S free classes today!

90 V

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

900 V

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.9 V

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $90 V$
Voltage in secondary coil $V_{s} = 9 V$
Turn ratio $\frac{N_{s}}{N_{p}} = 0.1$
Voltage in primary coil $V_{p} = \frac{N_{p}}{N_{s}} V_{s} = \frac{1}{0.1} \times 9 = 90 V$

Suggest Corrections

Similar questions

The turns ratio of a transformer is 15 and the primary AC voltage is 9 V. What is the secondary voltage of the coil?

Q. The primary coil of a transformer contains 100 turns; the secondary has 200 turns. The primary coil is connected to a size AA battery that supplies a constant voltage of 1.5 volts.The voltage in the secondary coil will be volts.

The primary coil of a transformer contains 100 turns; the secondary has 200 turns. The primary coil is connected to a size AA battery that supplies a constant voltage of 1.5 volts. What voltage would be measured across the secondary coil?

Q. A step-down transformer has primary voltage

1100

V

. The ratio of turns of primary to secondary coil is

5 : 1

. If the primary current is

10 A

then what is the secondary voltage and secondary current assuming the transformer to be an ideal transformer ?

Q. A power transformer has

50

turns for primary and

300

turns for secondary. What is turns ratio? How much is secondary voltage with primary voltage of

230

V

Join BYJU'S Learning Program

How many primary volts must be applied to a transformer with a secondary to primary turns ratio of 0.1 to obtain a secondary voltage of 9V?

The correct option is B 90VVoltage in secondary coil Vs=9 VTurn ratio NsNp=0.1Voltage in primary coil Vp=NpNsVs=10.1×9=90 V

How many primary volts must be applied to a transformer with a secondary to primary turns ratio of $0.1$ to obtain a secondary voltage of $9 V$ ?

The correct option is B $90 V$
Voltage in secondary coil $V_{s} = 9 V$
Turn ratio $\frac{N_{s}}{N_{p}} = 0.1$
Voltage in primary coil $V_{p} = \frac{N_{p}}{N_{s}} V_{s} = \frac{1}{0.1} \times 9 = 90 V$