MyQuestionIcon

5

You visited us 5 times! Enjoying our articles? Unlock Full Access!

Integers

How many prim...

Question

How many prime numbers less than $100$ leave an odd remainder when divided by $5$ ?

A

11

No worries! We‘ve got your back. Try BYJU‘S free classes today!

B

12

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C

13

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

D

14

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $13$
Prime numbers less than 100 that leave odd remainder when divided by $5$ are :

$3, 11, 13, 23, 31, 41, 43, 53, 61, 71, 73, 83, 93$

$\Rightarrow 13$ numbers

Suggest Corrections

thumbs-up

1

Similar questions

Q. How many numbers lie between 11 and 1111 which when divided by 9 leave a remainder of 6 and when divide by 21 leave a remainder of 12? ___

10^{x}

is divided by 13, remainder is 1. If x is a natural number less than 100, how many values can x take?

10^{x}

when divided by 13 leaves a remainder = -1. If x is a natural number less than 100, then how many solutions are possible for x?

Q. A number when divided by

7, 11

13

(the prime factor of

1001

) successively leave the remainder

6, 10

12

respectively. Find the remainder if the number is divided by

1001

.

Q. 10^x when divided by 13 remainder = -1. If x is a natural number less than 100 how many solutions are possible for x ?

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Integers

MATHEMATICS

Watch in App

explore_more_icon

Explore more

Standard VII Mathematics

Join BYJU'S Learning Program

CrossIcon