Question

How many products will be aromatic ion when $AgN{O}_3$ reacts with the following compounds.

Answer 1

Here, $4n+2=2$
$\Rightarrow n=0$
Thus it is aromatic.

Here, $4n=4$
$\Rightarrow n=1$, hence antiaromatic.

Here, $4n+2=6$
$\Rightarrow n=1$
Hence it is aromatic.


Here, $4n+2=6$
$\Rightarrow n=1$. Lone pair is involved in delocalisation.
Hence it is aromatic.
Here, $4n+2=6$
$\Rightarrow n=1$
Here both the starting material and the product is aromatic.

Other three compounds will not form $AgCl$ since they cannot form stable carbocation.