Question

How many products will be form in above reaction ?

• A. 2
• B. 4
• C. 3
• D. 6

Answer 1

Answer: (B)

4

As refer to the above image two chiral carbons with no meso form. So, No. of products $=2^2=4$

Here,

$2^n\to$ Given Isomers

$n\to$ No. of chiral carbons