Question

How many protons are present in 1.8g ${NH}_4^{+}$:
(1) $N_A$ (2) 1.2 $N_A$ (3) 1.1 $N_A$ (4) 11 $N_A$
Which of the following cannot exhibit geometrical isomerism?

Answer 1

1 mole of $N{H}_4^{+}$ has 7+4(1)=11 protons

$⟹$ 18g of $N{H}_4^{+}$ has=11 protons

$⟹$ 1.8g of $N{H}_4^{+}$ has=x protons

$⟹x=\frac{1.8\times 11}{18}=1.1moles=1.1N_A$ protons