Question

How many right angles are there in $\frac{3}{4}$ of a revolution?

Answer 1

We know that,

$1Revoloution={360}^0$

According to given question,

$\frac{3}{4}Revoloution=\frac{3}{4}\times {360}^0$

$=3\times {90}^0$

$={270}^0$

Now,

$\frac{3}{4}Revoloution={270}^0=3\times {90}^0$

$=3rightangles$

Hence, this is the answer.