Question

Question 2
How many shots each having diameter 3 cm can be made from a cuboidal lead solid of dimensions $9cm\times 11cm\times 12cm$ ?

Answer 1

Given , dimensions of cuboidal $=9cm\times 11cm\times 12cm$
$\therefore$ Volume of cuboidal $=9\times 11\times 12=1188c{m}^3$
And diameter of shot = 3 cm
$\therefore Radiusofshot,r=\frac{3}{2}=1.5cmVolumeofshot=\frac{4}{3}\pi r^3=\frac{4}{3}\times \frac{22}{7}\times (1.5{)}^3=\frac{297}{21}=14.143c{m}^3\therefore Requirednumberofshots=\frac{1188}{14.143}=84(approx.)$