Question

How many sides does a polygon have if the sum of the interior angles is: ${900}^o$

Answer 1

Since sum of the interior angles is ${900}^0$, therefore, $(2n–4){90}^0={900}^0$

$2n–4=\frac{900}{90}\Rightarrow 2n–4=10\Rightarrow 2n=10+4\Rightarrow 2n=14\Rightarrow n=\frac{14}{2}=7$

Hence, the polygon has $7$ sides.