Question

How many sides does a polygon have if the sum of the interior angles is $8$ right angles

Answer 1

We know that a right angle is of ${90}^0$.

Now, since sum of the interior angles is $8$ right angles, therefore, $(2n–4){90}^0=8\times {90}^0$

$2n–4=\frac{720}{90}\Rightarrow 2n–4=8\Rightarrow 2n=8+4\Rightarrow 2n=12\Rightarrow n=\frac{12}{2}=6$

Hence, the polygon has $6$ sides.