Question

How many sides does a polygon have if the sum of the interior angles is ${540}^o$?

Answer 1

Since sum of the interior angles is ${540}^0$, therefore, $(2n–4){90}^0={540}^0$

$2n–4=\frac{540}{90}\Rightarrow 2n–4=6\Rightarrow 2n=6+4\Rightarrow 2n=10\Rightarrow n=\frac{10}{2}=5$

Hence, the polygon has $5$ sides.