Question

How many sides does a regular polygon have if each of interior angle is ${60}^0$ ?

Answer 1

Sum of all angles of a regular polygon

having n sides= 180 (n-2)

$\Rightarrow \frac{180(n-2)}{n}={60}^{\circ }$

$180n-{360}^{\circ }=60n$

$120n={360}^{\circ }$

$n=3$

No. of sides = 3