How many $σ$ and $π$ bonds are presents in each of the following molecule?
(a) $H C \equiv C - C H = C H - C H_{3}$ (b) $C H_{2} = C = C H - C H_{3}$

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Solution

(a) $H - C \equiv C - C H = C H - C H_{3}$
$σ$ bond is a stronger bond than the $π$ bond.
No. of sigma bond $= 4 (C - C) + 6 (C - H) = 10$
No.of pi bond $= 3$

(b) $C H_{2} = C = C H - C H_{3}$
No. of sigma bonds $= 3 (C - C) + 6 (C - H) = 9$
No. of pi bonds $= 2$

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H C \equiv C - C H = C H - {C H}_{3}

σ

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C H_{3} - C H = C H - C \equiv C H

H C \equiv C - C H = C H - C H_{3}

C H_{3} - C H_{3}, C H_{2} = C H_{2}

C H \equiv C H

C H_{2} = C = C H - C H_{3}

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