Question

How many six-digit odd numbers, greater than $6,00,000$, can be formed from the digits $5,6,7,8,9$ and $0$ if repetition of digits is not allowed.

Answer 1

First place occupie by a numbers $6,7,8\&9$ and last place of digitd occupie by odd numbers and $0$ lof occupi 1st and 2nd position of digits.

Then, required number is

$$\begin{array}{c}4\left(firstplace\right)\times 5\times 6\times 6\times 6\times 3\left(lastplace\right)=12960\end{array}$$