The correct option is B 48
Let the side of big cube be 4cm. So, one side of smaller cube =1cm
n=sideofbigcubesideofsmallcube=41=4.
Number of smaller cube having less than three surfaces painted = Number of smaller cubes having 2 surfaces painted + Number of smaller cubes having one surface painted = Number of smaller cubes at 12 edges + Number of smaller cubes at six surface.
(n−2)×12+(n−2)2×6
=24+24=48.