How many smaller cubes will have no surface painted ?

0

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4

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8

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16

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Solution

The correct option is C $8$
Let the side of big cube be $4 c m$ . So, one side of smaller cube $= 1 c m$
$n = \frac{s i d e o f b i g c u b e}{s i d e o f s m a l l c u b e} = \frac{4}{1} = 4$ .
Number of smaller cubes having no surface painted $= (n - 2)^{3} \times 6 = (2)^{3} = 8$ .

Suggest Corrections

Similar questions

4 c m

1 c m

= \frac{4 \times 4 \times 4}{1 \times 1 \times 1} = 64

n = \frac{side of big cube}{side of small cube} = \frac{4}{1} = 4

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