Question

How many smaller cubes with two surfaces painted have one face green and one of the adjacent faces black or red ?

• A. $8$
• B. $16$
• C. $24$
• D. $28$

Answer 1

Answer: (B)

$16$

Let the side of big cube be $4cm$. So, one side of smaller cube $=1cm$
$n=\frac{sideofbigcube}{sideofsmallcube}=\frac{4}{1}=4$.
Number of smaller cubes having $2$ surfaces painted, having one face green and one of the adjacent faces black or red = Number of smaller cubes at $8$ edges $=(n-2)\times 8=2\times 8=16$.