How many solutions do the given equations have?

2x + 3y = 8,4x + 6y = 7.

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Solution

The correct option is A
0

2x + 3y = 8..................(1)

4x + 6y = 7..................(2)

Multiplying Equation (1) by 2

we get the equations as :

4x + 6y = 16...............(3)

4x + 6y = 7.................(2)

Subtracting Equation (2) from Equation (3),

(4x - 4x) + (6y - 6y) = 16 - 7

i.e., 0 = 9, which is not true

Therefore, given equations have no solution.

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Similar questions

x + 3 y = 7; 2 x + 6 y = m

m

5

2 x + 3 y = 6 4 x + 6 y = 12

How many solutions do the given equations have?
2+ 3= 8,4+ 6= 7.

Show graphically that each of the following given systems of equations has infinitely many solutions:

$2 x + 3 y = 6, 4 x + 6 y = 12.$

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