Given
A hydrogen atom, Having n2=5 and n1=1
Total no of the spectral lines =(n2−n1)(n2−n1−1)2
Here n2=5 and n1=1
Therefore the total no of the spectral line
(5−1)(5−1−1)2=202=10
So, the ten lines is
5→4,5→3,5→2,5→1,4→3,4→2,4→1,3→2,3→1,2→1 are
possible in this case.
Of all this lines only, one's falling in Balmer series are in visible region.
For Balmer series,x=2 and y=3,4,5
Thus,
5→2,4→2,3→2 it shows three lines lie in the visible region.