How many spoons can be electroplated by silver when $7$ ampere current is passed through electrolyte cell of $A g N O_{3}$ for $1.93$ hours? $0.01 g m A g$ layer is deposited on each spoon. $(A g = 108 g . m o l^{- 1})$ .

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Solution

Charge passed through the electrolyte:
$Q = I t$
$Q = 7 \times 1.93 \times 3600$ C
$Q = 48636 C$
Reduction process:
$A g^{+} + e \to A g$
One mole of electron charge ( $96500 C$ ) will produce 108 g Ag
Moles of electron $= \frac{48636}{96500} = 0.504$
Total silver deposited:
$= 0.504 \times 108 = 54.432 g$ Ag
coating on one spoon $= 0.01 g$ Ag
number of spoons coated $\times$ coating on 1 spoon = $54.432$
number of spoons coated = $\frac{54.432}{0.01}$
$= 5443$ spoons

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