How many stereoisomers does this molecule have? CH3CH=CHCH2CHBRCH3
A
8
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B
2
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C
4
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D
6
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Solution
The correct option is C 4
Both geometrical isomerism (cis-trans form) and optical isomerism is possible in the given compound. No. of optical isomer = 2n = 2’ = 2(n = no. of asymmetric carbon) Total no. of stereoisomers = 2 + 2 = 4