How many stereoisomers of (CH3)2CHCH=CHCH2CH(OH)CH2Cl are possible ?
A
2
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B
3
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C
4
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D
5
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Solution
The correct option is C 4
Four stereoisomers of (CH3)2CHCH=CHCH2CH(OH)CH2Cl are possible. It has one C=C double bond which shows E,Z isomerism and one chiral C atom which shows R/S isomers.