How many straight lines can be formed from $11$ points in a plane out of which no three points are collinear?

66

No worries! We‘ve got your back. Try BYJU‘S free classes today!

50

No worries! We‘ve got your back. Try BYJU‘S free classes today!

55

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

60

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $55$
Number of points $= 11$
No three are collinear
For a straight lines Two end points are needed
Number of straight lines needed
$\Rightarrow^{11} C_{2} \Rightarrow \frac{11!}{2! \times 9!} \Rightarrow \frac{11 \times 10}{2} \Rightarrow 55 l i n e s$
Option $: C$

Suggest Corrections

Similar questions

Out of 18 points in a plane, no three are in the same straight line except 5 points which are collinear. How many straight lines can be formed by joining them?

Q. How many straight lines can be formed with

6

points, no three of which are collinear

Out of 18 points in a plane, no three are in the same straight line except five points which are collinear. How many (i) straight lines (ii) triangles can be formed by joining them ?

Q. How many straight lines can be drawn with 18 points on a plane of which no points are collinear?

Q. Out of 18 points in a plane, no three are in the same straight line except five points which are collinear. How many
(i) straight lines
fill triangles can be formed by joining them?

Join BYJU'S Learning Program

How many straight lines can be formed from 11 points in a plane out of which no three points are collinear?

The correct option is C 55Number of points =11No three are collinearFor a straight lines Two end points are neededNumber of straight lines needed⇒11C2⇒11!2!×9!⇒11×102⇒55linesOption :C

How many straight lines can be formed from $11$ points in a plane out of which no three points are collinear?

The correct option is C $55$
Number of points $= 11$
No three are collinear
For a straight lines Two end points are needed
Number of straight lines needed
$\Rightarrow^{11} C_{2} \Rightarrow \frac{11!}{2! \times 9!} \Rightarrow \frac{11 \times 10}{2} \Rightarrow 55 l i n e s$
Option $: C$