How many structural isomers are possible $C_{4} H_{10} O$ (only alcohols)?

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Solution

The correct option is A 4
Solution:- (C) $4$
The no. of possible alcohol isomers for $C_{4} H_{10} O H$ is $4$ .
$C H_{3} - C H_{2} - C H_{2} - C H_{2} - O H \to$ Butan- $1$ -ol
$C H_{3} - C H_{2} - O H | C H - C H_{3} \to$ Butan- $2$ -ol
$C H_{3} - C H_{3} | C H | C H_{3} - O H \to 2$ -methylpropan- $2$ -ol
$C H_{3} - C H_{3} | C H - C H_{2} - O H \to 2$ -methylpropan- $1$ -ol

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