Question

How many structural isomers exist for $C_4{H}_{8}O$ which are ethers with no $s{p}^2$ hybridised atoms?

• A. 7
• B. 4
• C. 6
• D. 3

Answer 1

The correct option is A 7

For a compound with molecular formula $C_c{H}_h{X}_x{N}_n{O}_o$
$\text{Degree of unsaturation}=(c+1)-\frac{h}{2}-\frac{x}{2}+\frac{n}{2}$
Where, X = Halogen
c=number of carbon atom
h=number of hydrogen atom
n=number of nitrogen atom
o=number of oxygen atom
In $C_4{H}_{8}O$
$\text{Degree of unsaturation}=(4+1)-\frac{8}{2}=1$
Compound has one degree of unsaturation, it will have either one double bond or one ring. since there is no $s{p}^2$ hybridised atom it will contain a ring. Thus there are 7 possible structural isomers of $C_4{H}_{8}O$