How many structural isomers of the product B are possible?

(Give your answer in integer number)

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Solution

In the presence of KOH, 1-iodohexane undergoes dehydroiodination to form 1 hexene.

$C H_{3} C H_{2} C H_{2} C H_{2} C H_{2} C H_{2} - I + K O H (a l c .) d e h y d r o i o d i n a t i o n - ---------- \to C H_{3} C H_{2} C H_{2} C H_{2} C H = C H_{2}$

1-hexene reacts with $B r_{2} / C C l_{4}$ to form 1,2-dibromohexane.

$C H_{3} C H_{2} C H_{2} C H_{2} C H = C H_{2} + B r_{2} / C C l_{4} ⟶ C H_{3} C H_{2} C H_{2} C H_{2} C H (B r) C H_{2} B r$

When 1,2-dibromohexane is treated with sodaamide , it undergoes dehydrobromination to form 1-hexyne.

$C H_{3} C H_{2} C H_{2} C H_{2} C H (B r) C H_{2} B r + N a N H_{2} / N H_{3} d e h y d r o b r o m i n a t i o n - ----------- \to C H_{3} C H_{2} C H_{2} C H_{2} C \equiv C H$

A total of 3 structural isomers of the product B .

Hence, the correct answer is $3$

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