How many students play only hockey?

10

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

15

No worries! We‘ve got your back. Try BYJU‘S free classes today!

20

No worries! We‘ve got your back. Try BYJU‘S free classes today!

25

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $10$
Number of students who do not play any game is $h$
$a + b + c + d + e + f + g + h = 150$
$b + g = 20$
$e = 20$
$f = 35$
$d = 25$
$a = h$
$a = \frac{e}{2} = 10$
$h = a = 10$
$10 + 20 + c + 25 + 20 + 10 + 25 = 150$
$c = 30$
Number of students play only hockey is $10$

Suggest Corrections

Similar questions

Q. A group of 25 students play Hockey, Football and Cricket. 5 play all the three games, 12 play hockey and football only. 13 play football and cricket only. How many of them do not play any game?

Q44. A group of 25 students play Hockey, Football and Cricket. 5 play all the three games, 12 play hockey and football only. 13 play football and cricket only. How many of them do not play any game?

Q. In a class of 30 students, 20 play football, 14 play cricket, 10 play hockey. If no student play all 3 games and 8 students play none of the games, how many play cricket and hockey.

Q. How many play hockey only?

Q. In a group of children

35

play football out of which

20

play football only,

22

play hockey;

25

play cricket out of which

11

play cricket only. Out of these

7

play cricket and football but not hockey,

3

play football and hockey but not cricket and

12

play football and cricket both. How many play all three games?

Join BYJU'S Learning Program

How many students play only hockey?

The correct option is A 10Number of students who do not play any game is ha+b+c+d+e+f+g+h=150b+g=20e=20f=35d=25a=ha=e2=10h=a=1010+20+c+25+20+10+25=150c=30Number of students play only hockey is 10

The correct option is A $10$
Number of students who do not play any game is $h$
$a + b + c + d + e + f + g + h = 150$
$b + g = 20$
$e = 20$
$f = 35$
$d = 25$
$a = h$
$a = \frac{e}{2} = 10$
$h = a = 10$
$10 + 20 + c + 25 + 20 + 10 + 25 = 150$
$c = 30$
Number of students play only hockey is $10$