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Quantitative Aptitude

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How many stud...

Question

How many students prefer beverage Q and beverage T together?

A

2312

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B

2311

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C

2325

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D

2328

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E

None of these

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Solution

The correct option is A 2312
Number of students who prefer for beverages B and E together
$= (\frac{{57.6}^{\circ} + {64.8}^{\circ}}{360^{\circ}}) \times 6800 = \frac{{122.4}^{\circ}}{360^{\circ}} \times 6800 = 2312$

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