How many substances underlined have equivalent weight equal to molecular weight based on the reactions?
$H_{3} P O_{4} - ------ - + C a (O H)_{2} ⟶ C a H P O_{4} + 2 H_{2} O$
$H_{3} P O_{2} - ------ - + N a O H ⟶ N a H_{2} P O_{2} + H_{2} O$
$N a H C_{2} O_{4} - ---------- - + N a O H ⟶ N a_{2} C_{2} O_{4} + H_{2} O$

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Solution

In the first reaction, 2 H atoms are replaced. Hence, the equivalent weight will be one half the molecular weight.
In second and third reaction, only one hydrogen atom is replaced. Hence, the equivalent weight will be equal to molecular weight.
Hence, 2 substances underlined have equivalent weight equal to molecular weight based on the reactions.

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