How many such numbers are there which are equal to their cube but not equal to their square?
A
2
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B
1
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C
3
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Solution
The correct option is B 1 x^3=x x(x^2–1)=0 x=0 or x^2–1=0 x=0 or x=-1 or 1 0, -1, 1 are the only numbers whose cube root is same as the number, as you said the square root is different, we can eliminate zero and 1. So, the only option left is -1.