Question

How many tens are in the number $212$?

Answer 1

Find the number of tens in the given number:

Given that the number $212$:

Step-1: Find the number of $10\text{'}\mathrm{s}$.

To find the number of $10\text{'}\mathrm{s}$ in a particular number range, divide the number by $10$:

$\Rightarrow \mathrm{Number}\mathrm{of}10\text{'}\mathrm{s}=\frac{212}{10}$

Divide the expression:

$\begin{array}{rcl}& \Rightarrow & \mathrm{Number}\mathrm{of}10\text{'}\mathrm{s}=21.2\\ & \approx & 21\end{array}$

Rounding to the nearest whole number denotes the number of complete terms. So, the number of $10\text{'}\mathrm{s}$ is $21.$

Hence, the number of $\mathbf{10}\mathbf{\text{'}}\mathbf{s}$ included in the number $\mathbf{212}$ is $\mathbf{21}.$