How many terms are there in the AP whose first term is -8, 7th term is 34 and sum of all the terms is 615?
Sololution: Option (d)
First term is (a) = -8, 7th term is (a + 6d) = 34
6d = 42
d = 7
Sum of all the terms = [2a + (n- 1)d]
615 = (-16 + (n – 1)7)
Solving we get n = 15, i.e. 15 terms are there in the A.P.