How many terms are there in the product of $(8 x - 3 y)$ and $(8 x + 3 y)$ ?

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Solution

The correct option is A 2
$(8 x - 3 y) \times (8 x + 3 y) = 8 x \times (8 x + 3 y) - 3 y \times (8 x + 3 y) = 8 x \times 8 x + 8 x \times 3 y - 3 y \times 8 x - 3 y \times 3 y = 64 x^{2} + 24 x y - 24 x y - 9 y^{2} = 64 x^{2} - 9 y^{2}$

Hence, there are 2 terms in the product of $(8 x - 3 y)$ and $(8 x + 3 y)$ .

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8 x + 3 y

3 x^{2}

\begin{matrix} 8 x - 3 y = 1 34 x - 3 y = 4 \end{matrix}

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