Question

How many terms are there in the sequence 3, 6, 9, 12, ... 111 ?

• A. 35
• B. 36
• C. 37
• D. 38

Answer 1

The correct option is C 37

Here, $a=3,d=3$

$a_n=111$

$a+(n-1)d=111$

$3+(n-1)\left(3\right)=111$

$n=37$

Hence, the sequence contains 37 terms.