Question

How many terms are there in the set of consecutive integers from $-18$ to $33$, inclusive?

• A. $54$
• B. $51$
• C. $52$
• D. $55$

Answer 1

Answer: (C)

$52$

Let $a=-18$

$d=1$

$a_n=33$

To find n:

$a_n=a+(n-1)d$ .......(Formula for $n^{th}$ term of an A.P.)

$33=(-18)+(n-1).1$

$51=n-1$

$\therefore n=52$ (Ans $\to$C)