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Question

How many terms of the geometric progression 1 + 4 + 16 + 64 + ........ must be added to get sum equal to 5461 ?

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Solution

let n terms make it sum 5461 .

now ,first term ,a =1 , common ratio ,r =4 .

then we can say ,fraction numerator 4 to the power of n minus 1 over denominator 3 end fraction =5461

= 4n-1 = 16383

= 4 to the power of n= 16384

= n =7 . so , 7 terms of his series will make the sum of 5461


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