CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

How many terms of the geometric progression 1 + 4 + 16 + 64 + ........ must be added to get sum equal to 5461 ?

Open in App
Solution

let n terms make it sum 5461 .

now ,first term ,a =1 , common ratio ,r =4 .

then we can say ,fraction numerator 4 to the power of n minus 1 over denominator 3 end fraction =5461

= 4n-1 = 16383

= 4 to the power of n= 16384

= n =7 . so , 7 terms of his series will make the sum of 5461


flag
Suggest Corrections
thumbs-up
13
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Sum of n Terms
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon