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Question

How many terms of the given G.P. 3,32,34,,. be taken together to get 3069512?

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Solution

a=3

r=3/23=12

Sn=a(rn1)r1

3069512=3((12)n1)(121)

3069512=6[1(12)n]

30693072=1(12)n

(12)n=130693072

(12)n=33072

(12)n=11024

(12)n=(12)10

n=10

So, 10 terms are required.

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