How many terms of the series 1+3+9+......., sum to 1093?
A
5
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B
6
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C
7
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D
3
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Solution
The correct option is B 7 the given series is a G.P sum of n terms of a G.P is a∗((rn−1)(r−1)) here a=1 and r=3 So, 1∗((3n−1)(3−1))=1093 Thus, ((3n−1)2)=1093