How many thousand litres of carbon monoxide at $25^{\circ} C$ and 740 mm $H g$ are obtained as a by-product? Round of the answer to the nearest integer
$(C r = 52, F e = 56, C = 12, O = 16)$

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Solution

224 kg chromite gives 112 kg $C O$
Thus, 236 kg chromite gives $\frac{112 \times 236}{224}$ kg $C O$
= 118 kg $C O$ = 4214.2857 mol
Using equation $p V = n R T : T = 298 K, p = \frac{740}{760} a t m$
V = $\frac{n R T}{P}$ = $\frac{4214.2857 \times 0.0821 \times 298}{(740 / 760)}$
= $105.892 \times 10^{3} L C O$

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