Question

How many three digit natural numbers are divisible by 4?

• A. 224
• B. 225
• C. 226
• D. 227

Answer 1

The correct option is B 225

First three digit number divisible by $4$ is $100$ and last three digit number divisible by $4$ is $996$.

So, we have to find the number of terms in the sequence. $100,104,108,...,996.$
Here, $a=100,d=4.$
Let there be n terms in this sequence. Then,
$a_n=996\Rightarrow a+(n-1)d=996$
$\Rightarrow 100+(n-1)4=996$
$\Rightarrow n-1=224\Rightarrow n=225$