Question

How many three-digit numbers are possible using the digits 7, 3, and 9 without repeatition?​

• A. 6

Answer 1

The correct option is A 6
We know that, systematic listing helps in listing of all possible outcomes for an event in an organised/systematic way.
The possible numbers are:
(i) 739
(ii) 793
(iii) 379
(iv) 397
(v) 973
(vi) 937

$\therefore$ there are six numbers that can be formed using the given digits.