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Question

How many three digit numbers leave a remainder 3 on division by 4?

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Solution

1st three-digit number which leaves the remainder 3 when divided by 4 = 103

2nd three-digit number which leaves the remainder 3 when divided by 4 = 107

3rd three-digit number which leaves the remainder 3 when divided by 4 = 111

nth three-digit number which leaves the remainder 3 when divided by 4 = 999

So, the arithmetic sequence is 103, 107, 111, … , 999

Common difference = 107 − 103 = 4

To get the nth three-digit number from the 1st three-digit number, we must add the common difference (n 1) times to the 1st three-digit number.

999 = 103 + (n − 1) × 4

999 − 103 = 4n − 4

4n − 4 = 896

4n = 900

n = 225

Thus, there are 225 three-digit numbers which leaves the remainder 3 when divided by 4.


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