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Question

How many three digit odd numbers can be formed by using the digits 1,2,3,4,5,6 if the repetition of digit is not allowed:

A

216

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B

120

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C

60

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D

None of these

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Solution

The correct option is C 60 For a number to be odd, we must have 1,3 or 5 at the unit's place. So there are 3 ways for filling the unit's place. Since the repetition of digits is not allowed, the ten's place can be filled with any of the remaining 5 digits in 5 ways. Now, four digits are left, so hundred's place can be filled in 4 ways. So, required number of numbers = 3 x 5 x 4 = 60

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