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Question

How many three digit odd numbers can be formed by using the digits 1,2,3,4,5,6 if the repetition of digit is not allowed:


  1. 216

  2. 120

  3. 60

  4. None of these


Solution

The correct option is C

60


For a number to be odd, we must have 1,3 or 5 at the unit's place.  So there are 3 ways for filling the unit's place.

Since the repetition of digits is not allowed, the ten's place can be filled with any of the remaining 5 digits in 5 ways.  Now, four digits are left,  so hundred's place can be filled in 4 ways.

So, required number of numbers = 3 x 5  x 4 = 60

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