Question

How many time will the wheel of a can rotation in a iorrney of 88 km, given that the diameter of the wheel is 56 cm?

Answer 1

Circumference = $2\pi r=1$ revolution

D= 56 cm, $r=\frac{56}{2}=28cm$

$\therefore 2\pi r=2\times \frac{22}{7}\times 28=44\times 4=176cm$

For 176 cm, wheel rotates 1 time

$\therefore$ for $88km=88\times 1000\times 100cm$, wheel rotates = $\frac{1}{176}\times 8800000$

= 50000 times.