Question

How many times does the electron go round the first Bohr orbit of hydrogen atoms in 1 s? (in peta Hz)

Answer 1

Here, we have to find the frequency which is given as:
$f=\frac{m{Z}^2{e}^4}{4{ϵ}_0^2{n}^3{h}^3}$
$=\frac{9.1\times {10}^{-31}\times 1^2\times (1.6\times {10}^{-19}{)}^4}{4\times (8.85\times {10}^{-12}{)}^2\times 1^3\times (6.6\times {10}^{-34}{)}^3}$
$=6.62\times {10}^{15}Hz$