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Question

How many times does the electron of hydrogen atom go round the first Bohr orbit in one second?
[m=9.1×1031 kg, e=1.6×1019 Cε0=8.85×1012 F m1, h=6.6×1034 J s]

A
6.6×105
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B
6.6×1010
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C
6.6×1013
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D
6.6×1015
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Solution

The correct option is D 6.6×1015
Here, we have to find frequency which is given by,

ν=mZ2e44ε20n3h3

For Hydrogen atom Z=1 and for first Bohr orbit, n=1

ν=9.1×1031×(1.6×1019)49×(8.85×1012)2×(1)3×(6.6×1034)2

=59.63×101079.00×10122=6.6×1015 Hz

<!--td {border: 1px solid #ccc;}br {mso-data-placement:same-cell;}--> Hence, (D) is the correct answer.

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